(2^2x+2)(2^3x-7)=2^25

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Solution for (2^2x+2)(2^3x-7)=2^25 equation: 



(2^2x+2)(2^3x-7)=2^25

We move all terms to the left:

(2^2x+2)(2^3x-7)-(2^25)=0

We add all the numbers together, and all the variables

(2^2x+2)(2^3x-7)-33554432=0

We move all terms containing x to the left, all other terms to the right

(2^2x+2)(2^3x-7)=33554432

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